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Haskell frequency function

I want to write a function that returns the frequency of each number in a list of integers.
For example, if I have the list [5,1,4,1,4,1,5,4,5,5,5,5,3,5,4,2,5], my function should return [ [1,5,2,2] ].
What is the most efficient way to write this function?
Thanks.

A:

You can use zipWith (*) which is more efficient than a list comprehension, but it’s not as easy as the “letter-by-letter” answer:
listFrequency :: [Int] -> [Int]
listFrequency [] = []
listFrequency (x:xs) = zipWith (*) xs x

This of course wouldn’t be the most efficient way to implement listFrequency in Haskell, as * is quite expensive.
E.g. here is a O(n):
count :: Int -> Int
count x = let (y,z) = span (==x). map (\y -> y*) $ count’ [1..x] in y*z

Q:

pthread_create() and linux

I’ve got a function that I use to create the threads that communicate between each other through a unix domain socket. The socket is localhost and communication happens between the two processes over this socket.
My question is the following. It is unknown at compilation time which process is going to create the thread. If for example the thread_t* p is of process I can’t create in the same way a thread of process Y?
void* NetworkManager::run() {
pthread_t thread_t;
pthread_attr_t attr;

pthread_attr_init(&attr);
pthread_attr_setdetachstate(&attr, PTHREAD_CREATE_DETACHED);
pthread_create(&
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